![]() This means the journal is among the top 3% in the science branch of Physical Sciences. This Journal is the 316 th out of 12,155 Physical Sciences journals. This means the journal is among the top 3% in the science branch of Applied Sciences. This Journal is the 155 th out of 5,488 Applied Sciences journals. This means the journal is among the top 2% in the science branch of Formal Sciences. This Journal is the 46 th out of 3,140 Formal Sciences journals. This means the journal is among the top 4% in the discipline of Computer Science. This Journal is the 33 rd out of 1,027 Computer Science journals. This means the journal is among the top 4% in the sub-discipline of Software Engineering. This Journal is the 24 th out of 734 Software Engineering journals. This means the journal is among the top 6% in the sub-discipline of Artificial Intelligence. How Influential is Expert Systems With Applications? Expert Systems With Applications is the 19 th out of 340 Artificial Intelligence journals. Impact Factor is the most common scientometric index, which is defined by the number of citations of papers in two preceding years divided by the number of papers published in those years. 2 × -2 = 4, so we can see that the factored terms in parentheses multiply to become the original equation.- Re-Draw The graph shows the changes in the impact factor of Expert Systems With Applications and its the corresponding percentile for the sake of comparison with the entire literature. In this case, adding a -2 to both blank spaces gives the correct answer. Expert Systems With Applications is currently ranked number 1 in the Google Scholar h-index listed under the top publications of Artificial Intelligence. However, once we realize that 3 only has two factors (3 and 1), it becomes easier, because we know that our answer must be in the form (3x +/- _)(x +/- _). ![]() 3x 2 - 8x + 4 at first seems intimidating. If both are 1, you've essentially used the shortcut described above. Either d or e (or both) can be the number 1, though this is not necessarily so. If the equation is in the form ax 2+bx+c and a>1, your factored answer will be in the form (dx +/- _)(ex +/- _), where d and e are nonzero numerical constants that multiply to make a. This is also known as factoring by inspection. Believe it or not, for uncomplicated quadratic equations, one of the accepted means of factoring is simply to examine the problem, then just consider possible answers until you find the right one. Note: the numbers in the blanks can be fractions or decimals.If it is in the form x 2-bx-c, you answer is in the form (x + _)(x - _).If it is in the form x 2+bx+c, your answer looks like this: (x + _)(x + _).If the quadratic equation is in the form x 2-bx+c, your answer is in this form: (x - _)(x - _).Slight variations on this basic shortcut exist for slight variations in the equation itself:.3 and 2 multiply together to make 6 and also add up to make 5, so we can simplify this equation to (x + 3)(x + 2). For example, let's consider the quadratic equation x 2 + 5x + 6 = 0.These two terms, when multiplied together, produce your quadratic equation - in other words, they are your quadratic equation's factors. Once you find these two numbers d and e, place them in the following expression: (x+d)(x+e). Find two numbers that both multiply to make c and add to make b. If your quadratic equation it is in the form x 2 + bx + c = 0 (in other words, if the coefficient of the x 2 term = 1), it's possible (but not guaranteed) that a relatively simple shortcut can be used to factor the equation. In quadratic equations where a = 1, factor to (x+d )(x+e), where d × e = c and d + e = b. x/2 + 4, for instance, can be simplified to 1/2(x + 8), and -7x + -21 can be factored to -7(x + 3). This process also applies to equations with negatives and fractions.6 is the biggest number that divides evenly into both 12x and 6, so we can simplify the equation to 6(2x + 1). To factor the algebraic equation 12 x + 6, first, let's try to find the greatest common factor of 12x and 6. This simplification process is possible because of the distributive property of multiplication, which states that for any numbers a, b, and c, a(b + c) = ab + ac. Usually, to make the equation as simple as possible, we try to search for the greatest common factor. Using your knowledge of how to factor both lone numbers and variables with coefficients, you can simplify simple algebraic equations by finding factors that the numbers and variables in an algebraic equation have in common. Apply the distributive property of multiplication to factor algebraic equations.
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